Chapter 6: Analysis of Rate | Estimating & Costing (ENCE 351)
Analysis of Rate in Estimating and Costing - ENCE 351
ESTIMATING AND COSTING (ENCE 351)
Chapter 6: Analysis of Rate
6 Hours | 8 Marks

Analysis of Rate in Estimating and Costing

Syllabus: Analysis of Rate (6 Hours)

6. Analysis of Rates (6 hours)

6.1 Importance and purpose of rate analysis

6.2 Data required for rate analysis

6.3 Factors affecting rate analysis

6.4 Prevailing rate analysis norms and district rates in Nepal

6.5 Analysis of rate

6.5.1 Building works: Brickwork, concrete work, reinforcement work, woodwork, plasterwork, and flooring work

6.5.2 Road works: Earthwork in excavation/filling using equipment; Gabion, stone masonry, plum concrete, and pavement works

6.5.3 Sanitary and water supply works: Wash basin; commode and pan; pipes and fittings

Copyright & Credit: All copyrights and intellectual property rights of the original materials belong to Er. Pradeep Bhatta Sir. These notes are prepared for educational and reference purposes with due acknowledgment of the original source.

Analysis of Rate Notes

1. What is Rate Analysis?

The method of determining the rate per unit of a particular item of work, considering the cost and quantities of materials, cost of labour (skilled and unskilled), hire of tools and plants, and contractor’s profit, etc., is known as Rate Analysis.

The rate of material is usually taken as the rate delivered at the site of work and includes the first cost (cost of origin), cost of transport, taxes, etc. If materials are to be carried from a distant place, more than 8 km, the cost of transportation is also added. The rate of materials and labour vary from place to place, and therefore the rate of a different item of work also varies from place to place.

2. Purpose of Rate Analysis

The purpose of rate analysis can be summarized as follows:

  • To work out the actual cost per unit of an item.
  • To work out the economical use of materials.
  • To work out the cost of extra items which are not provided in the contract documents (Bill of Quantities – BOQ).
  • To revise the schedule of rates due to changes in construction technique.

3. Requirement of Rate Analysis

  1. Correct information of the market rate of materials.
  2. Correct information of the rate of various categories of labour.
  3. Output of labour.
  4. Knowledge, rate, and outturn of various types of plant to be used in the construction work.
  5. Up-to-date knowledge of construction.
  6. Standards norms.

4. Factors Affecting Rate Analysis

  1. Specification of work and quality of materials.
  2. Proportion of mix (concrete or mortar).
  3. Construction facilities and availability of materials, tools, and plants.
  4. Location of site.
  5. Cost of labours and their availability.
  6. Facilities available for transportation of materials and labours to the site.
  7. Condition of road to the worksite.
  8. Overhead charges.

The rate of a particular item of work depends on the following:

  • Specification of different items of work and materials to be used.
  • Quantities of materials and their rates, number of different types of labours (skilled/unskilled).
  • Location of work site, means of communication, distance of site from the sources of materials, rates of transportation, availability of workers.
  • Availability of tools and plants, different types of equipment for different operations as per specification.
  • Profit and overhead expenses of contractors.

5. Importance of Rate Analysis

  1. The process of doing analysis gives a clear picture of the various types of labours and materials required for completing the particular work.
  2. It can be used frequently to settle the disputes between contractor and client about the item not included in the original estimate.
  3. It can be used for the compensation by insurance.

Material Estimate

Note (Dry Mix / Wastage Norms)

  1. In concrete mix: To get dry mix (Cement + Sand + Aggregates), increase 50% to 55% of wet mix.
  2. In mortar mix: To get dry mix (Cement + Sand), increase 30% to 35% of wet mix.
  3. In plastering works: Firstly, increase 25% for filling in between joints and irregular surface. In case of ceiling and concrete surface (plain surface), only 10% – 15% increase of wet mix to get total wet mix. Then, to get dry mix (Cement + Sand), increase 30% to 35% of wet mix.
  4. In case of stone works: To get required stone, 15% – 20% increase of total works due to wastage and dressing. Volume of dry mortar mix = 30% to 40% of stone masonry.
  5. In RCC work: To get reinforcement: 1-3% of volume of RCC. Loss during cutting (but no lap and chair length included) = 5%. Binding wire: 10 Kg per quintal.

Calculate the Quantities of Materials Required for the Following Items of Work

Example 1: 48.5 m³ of brick work in (1:3) cement sand mortar.

Volume of brick work = 48.5 m³. Assume brick size = 230mm x 110mm x 55mm; mortar thickness = 10mm; so brick size with mortar = 240mm x 120mm x 65mm.

No. of bricks required $= \dfrac{\text{Vol. of brick work}}{\text{Vol. of one brick with mortar}} = \dfrac{48.5}{0.24 \times 0.120 \times 0.065} = 25908.11 \approx 25909$ Nos.

Add 5% wastage $\therefore$ Brick required $= 1.05 \times 25909 = 27205$ Nos.

Volume of wet mortar = Total brick work – Actual vol. of brick (without mortar) $= 48.5 – 25908.11 \times (0.23 \times 0.11 \times 0.055) = 12.45\text{ m}^3$

To get dry vol. of mortar, 30% increase: Dry vol. of mortar $= 1.3 \times 12.45 = 16.90\text{ m}^3$

Total part of mix proportion $= 1 + 3 = 4$

$\therefore$ Required cement $= \dfrac{16.90}{4} = 4.05\text{ m}^3$ {Unit wt. of cement = 1440 kg/m³, 1 bag cement = 50 kg} $= 4.05 \times 28.8 = 116.57$ bags

$\therefore$ Required sand $= 3 \times 4.05 = 12.15\text{ m}^3$

Let water cement ratio $= 0.8$; Water $= 0.8 \times 116.57 \times 50 = 4662.8$ lit

Hence, Required: Bricks = 27205 Nos, Cement = 116.57 bags, Sand = 12.15 m³, Water = 4662.8 lit.

Example 2:15 cm thick Foundation PCC (1:3:6), 0.95 m wide and 42 m long.

Total quantity of work (PCC) $= 42 \times 0.95 \times 0.15 = 5.99\text{ m}^3$

To get dry vol. of concrete mix, increase 50% to 55%: Vol. of dry mix $= 1.5 \times 5.99 = 8.99\text{ m}^3$

Total part of mix proportion $= 1 + 3 + 6 = 10$

Required: Cement $= 8.99 \times \dfrac{1}{10} = 0.899\text{ m}^3 = 0.899 \times 28.8 = 25.89$ bags

Sand $= 0.899 \times 3 = 2.697\text{ m}^3$; Aggregate $= 0.899 \times 6 = 5.394\text{ m}^3$

Water/Cement $= 0.5$; Water $= 0.5 \times 25.89 \times 50 = 647.25$ lit

Example 3: PCC – M20 for RCC roof 100mm thick, 20m wide and 25 m long.

PCC for RCC work $= 25 \times 20 \times 0.10 = 50\text{ m}^3$

Increase 50% for getting dry volume of mix: Vol. of dry mix $= 1.5 \times 50 = 75\text{ m}^3$

Total part of mix proportion $= 1 + 1.5 + 3 = 5.5$

Required: Cement $= 75 \times \dfrac{1}{5.5} = 13.636\text{ m}^3 = 13.63 \times 28.8 = 392.72$ bags

Sand $= 13.636 \times 1.5 = 20.45\text{ m}^3$; Aggregate $= 13.636 \times 3 = 40.91\text{ m}^3$

Water/Cement $= 0.5$; Water $= 0.5 \times 392.72 \times 50 = 9818$ lit

Mild Steel Bars (Steel Reinforcement): 1% of PCC for RCC work $= 1\%$ of $50\text{ m}^3 = 0.01 \times 50 = 0.5\text{ m}^3$ {Unit wt. of steel = 7850 kg/m³} $= 0.5 \times 7850 = 3925.00$ Kg

Binding wire $= 1$ kg per quintal $= 1 \times \dfrac{3925}{100} = 39.25$ kg

Example 4: 713 m² of 12.5 mm thick cement plaster (1:4).

Quantity of plastering work $= 713\text{ m}^2$. Therefore, Vol. of wet mortar $= 713 \times 0.0125 = 8.91\text{ m}^3$

Firstly, increase 25% for filling in between joints and irregular surface to get total wet mix $= 1.25 \times 8.91 = 11.14\text{ m}^3$

To get dry vol. of mortar, 30% increase: Vol. of dry mortar $= 1.30 \times 11.14 = 14.48\text{ m}^3$

Total part of mix proportion $= 1 + 4 = 5$

Required: Cement $= \dfrac{1}{5} \times 14.48 = 2.896\text{ m}^3 = 2.896 \times 28.8 = 83.42$ bags

Sand $= 2.896 \times 4 = 11.58\text{ m}^3$

Let water cement ratio $= 0.8$; Water $= 0.8 \times 83.42 \times 50 = 3336.8$ lit

Example 5: 110 m² half brick thick wall in (1:3) cement mortar.

Quantity of work $= 110\text{ m}^2$. Vol. of brick work $= 110 \times 0.11 = 12.10\text{ m}^3$

Assume brick size 230mm x 110mm x 55mm; brick size (with 10mm mortar) $= 240$mm x 110mm x 65mm.

No. of bricks required $= \dfrac{\text{Vol. of brick work}}{\text{Vol. of one brick with mortar}} = \dfrac{12.1}{0.24 \times 0.110 \times 0.065} = 7051.28 \approx 7052$ Nos.

Add 5% wastage $\therefore$ Brick required $= 1.05 \times 7052 = 7405$ Nos.

Volume of wet mortar = Total brick work – Actual vol. of brick (without mortar) $= 12.1 – 7052 \times (0.23 \times 0.11 \times 0.055) = 2.287\text{ m}^3$

To get dry vol. of mortar, 30% increase: Dry vol. of mortar $= 1.3 \times 2.287 = 2.97\text{ m}^3$

Total part of mix proportion $= 1 + 3 = 4$

$\therefore$ Required cement $= \dfrac{2.97}{4} = 0.74\text{ m}^3$ {Unit wt. of cement = 1440 kg/m³, 1 bag cement = 50 kg} $= 0.74 \times 28.8 = 21.41$ bags

$\therefore$ Required sand $= 3 \times 0.74 = 2.22\text{ m}^3$

Let water cement ratio $= 0.8$; Water $= 0.8 \times 21.41 \times 50 = 856.40$ lit

Example 7: 10 m³ of stone masonry in 1:6 mortar ratios.

Quantity of stone masonry $= 10\text{ m}^3$. Required: Vol. of stone $= 1.15 \times 10 = 11.5\text{ m}^3$

Vol. of dry mortar $= 40\%$ of work quantity $= 0.4 \times 10 = 4\text{ m}^3$

Total part of mix proportion $= 1 + 6 = 7$

Required cement $= \dfrac{1}{7} \times 4 = 0.57\text{ m}^3 = 0.57 \times 28.8 = 16.45$ bags

Required sand $= 6 \times 0.57 = 3.42\text{ m}^3$

W/C $= 0.6$; Required water $= 0.6 \times 16.45 \times 50 = 493.5$ lit

Norms and Standards of Nepal for Rate Analysis

1.0 Tree Cutting

DescriptionUnskilled LabourTransport Distance
Cutting
ɸ 12-30 cm of girth0.1315m
ɸ 31-60 cm girth0.3915m
ɸ 61-120 cm girth0.9815m
Un-rooting
ɸ 12-30 cm0.4015m
ɸ 31-60 cm0.5215m
ɸ 61-120 cm2.5215m

2.0 Brick Work

Remark: For G.F. (Ground Floor) 0.2, For F.F. (First Floor) 0.7 (additional labour factor by floor level).

DescriptionSkilledUnskilledTransportUnit
Brick work (1:3)1.52.230mcum
Brick work (1:4)cum
Brick work (1:5)cum
Brick work (1:6)cum

3.0 Stone Work

DescriptionSkilledUnskilledTransportUnit
Rubble stone masonry (1:3 – 1:6)1.5510mcum
Rubble Arch (1:3 – 1:6)25.410mcum
Rubble stone masonry (Dry)1210mcum
Broken stone1.5310mcum

4.0 PCC Work

DescriptionSkilledUnskilledTransportUnit
PCC (1:2:4)1430mcum
PCC (1:3:6)cum
PCC (1:4:8)cum
PCC (1:5:10)cum

5.0 PCC for RCC Work

DescriptionSkilledUnskilledTransportUnit
PCC for RCC (1:2:4)0.8730mcum
PCC for RCC (1:1.5:4)cum
PCC for RCC (1:1:2)cum

Remark: If Mixture (0.6 hr) + Vibrator (0.25 hr): Skilled 0.5, Unskilled 3.5

6.0 Flooring Work

DescriptionSkilledUnskilledUnitRemarks
38 mm thick Punning (1:2:4)1.25210 sqm
50 mm thick Punning (1:2:4)2.2510 sqm
75 mm thick Punning (1:2:4)310 sqmTBC

7.0 Soling Work

DescriptionSkilledUnskilledUnitBrick (Nos.)Cement, C (m³)Sand, S (m³)
Flat Brick soling (1:6 with pointing)2.253.2510 sqm4300.0780.23
Edge Brick soling (1:6 with pointing)1.11.810 sqm7500.1210.43
FBS Dry0.5110 sqm4200.71
EBS Dry13.2510 sqm7500.71
Flat stone soling dry13.510 sqm1.1 m³ (stone)0.71

8.0 Plaster Work

DescriptionSkilledUnskilledUnit
12.5mm thick cement plaster (1:3 – 1:6)1216100 sqm
For ceiling1220100 sqm
20mm thick cement plaster (1:3 – 6)1419100 sqm

9.0 Sanitary Fixture

DescriptionSkilledUnskilledUnit
Water closet commode with low level cistern33no
Water closet pan with low level cisternno
Wash basin22no
Kitchen sinkno

10.0 Form Work

DescriptionSkilledUnskilledTransportUnitWoodNail
FW Column3.7485.62230m10sqm0.07 cum2.5 kg
FW Beam & slab4630m10sqm0.07 cum2.5 kg
FW beam up to 0.3 – 0.8m2.67430m10sqm0.07 cum2.5 kg
FW (Trench up to 3m)0.51100sqm4.16 sqm2.5 kg
FW (Trench >3m)11.75100sqm4.16 sqm2.5 kg

11.0 Roofing

DescriptionSkilledUnskilledUnitMaterial
CGI 0.75mm thick1.11.2510 sqmCGI – 12 sqm
Slate4510 sqmSlate – 24 sqm
Clay tile0.51.510 sqmClay tile – 127
Clay tile dhuri0.50.510 rmTile – 27

12.0 Wood Work

DescriptionSkilledUnskilledUnitWoodH.F. (No.)Nail
Wooden frame (agrakh)343.4cum1.192184
38mm thick Agrakh Frame with panel (measurement 1.829 x 1.22 = 2.114 sqm)101sqm0.084 cum100mm hinge – 6, 250mm locking set – 1, handle – 2, tower bolt – 2nail – L.S.

13.0 Painting Work

Remark: For ceiling, unskilled labour increased by 25%.

DescriptionSkilledUnskilledUnitPaintGum / Primer
Whitewash 1 coat0.80.7100sqm12 kgGum 0.48 kg
Whitewash 2 coat1.51.1100sqm22 kgGum 0.88 kg
Whitewash 3 coat32.7100sqm32 kgGum 1.28 kg
Distemper 1 coat44100sqm8 litPrimer 6.5 kg
Distemper 2 coat5.85.8100sqm8 litPrimer 11.5 kg
Waterproof paint 1 coat1.71.7100sqm30 kg
Waterproof paint 2 coat55100sqm48.5 kg
Enamel paint 1 coat85100sqm9 litPrimer 8.1 lit
Enamel paint 2 coat128100sqm16 litPrimer 8.1 lit
Emulsion paint 1 coat85100sqm9 litPrimer 8.1 lit
Emulsion paint 2 coat128100sqm16 litPrimer 8.1 lit
Aluminium paint 2 coat10.7510.75100sqm10.76 litPrimer 8.1 lit
Varnish 1 coat32100sqm6 lit
Varnish 2 coat64100sqm11 lit
Chapra polish 3 coat105100sqm2 kgSprit – 10 lit

Road Works Norms

S.N.DescriptionUnitLabour (Class – Qty)Material (Type – Qty)Equipment (Type – Qty)
1. Preparation of subgrade in ordinary soil cutting: 10m lead
i)Upto 10cm depthUnskilled 0.12
ii)Upto 20cm depthUnskilled 0.18
iii)Upto 30cm depthUnskilled 0.24
2. Preparation of subgrade in stone mixed soil cutting: 10m lead
i)40-60% stone mixed: upto 10cm depthUnskilled 0.29
ii)40-60% stone mixed: upto 20cm depthUnskilled 0.41
iii)40-60% stone mixed: upto 30cm depthUnskilled 0.53
3. Providing & spreading approved size gravel in sub-grade: 10m lead (loose gravel +35%)
i)10cm thick (compacted)Unskilled 0.14Gravel 0.135 m³Road Roller 0.028 hr
ii)15cm thick (compacted)Unskilled 0.21Gravel 0.203 m³Road Roller 0.042 hr
iii)25cm thick (compacted)Unskilled 0.32Gravel 0.337 m³Road Roller 0.070 hr
4. Compaction by 8-10 ton Road Roller
i)Sub Base Course100 m³Road Roller 3 hr
ii)Base Course100 m³Road Roller 4 hr
5. Providing & laying crushed stone, sand & clay base course (clay bound macadam): 10m lead
i)6cm compacted thicknessUnskilled 0.10Coarse Agg 0.0794 m³, Screening 0.016 m³, B. material 0.007 m³Road Roller 0.0024 hr
ii)7.5cm compacted thicknessUnskilled 0.12Coarse Agg 0.10 m³, Screening 0.02 m³, B. material 0.009 m³Road Roller 0.003 hr
iii)10cm compacted thicknessUnskilled 0.13Coarse Agg 0.1087 m³, Screening 0.021 m³, B. material 0.0096 m³Road Roller 0.0032 hr
6. Providing & laying crushed stone and stone dust (stone bound macadam): 10m lead
i)6cm compacted thicknessUnskilled 0.10Coarse Agg 0.0794 m³, Stone dust 0.016 m³Road Roller 0.0024 hr
ii)10cm compacted thicknessUnskilled 0.15Coarse Agg 0.1087 m³, Stone dust 0.0213 m³Road Roller 0.0032 hr
iii)15cm compacted thicknessUnskilled 0.23Coarse Agg 0.20 m³, Stone dust 0.04 m³Road Roller 0.006 hr
7. Providing & laying Base Course of crushed stone
i)10cm thick (compacted)Unskilled 0.1575mm c.stone 0.148 m³Road Roller 0.004 hr
ii)7.5cm thick (compacted)Unskilled 0.1250mm c.stone 0.10 m³Road Roller 0.003 hr
8. Providing & laying Tack coat
i)Over old pitch surface10 m²Unskilled 0.20Bitumen 7.3 Kg, Kerosene L.S, Wood (Boiler) 3 Kg, Wood (open area: mass work) 12 Kg, Wood (open area: patch work) 18 KgBoiler & sprayer 0.04 hr
ii)Over Base course10 m²Unskilled 0.20Bitumen 12.2 Kg, Kerosene L.S, Wood (Boiler) 5 Kg, Wood (open area: mass work) 20 Kg, Wood (open area: patch work) 30 KgBoiler & sprayer 0.04 hr
9. Providing & laying priming coat
i)Over old pitch surface10 m²Unskilled 0.20Bitumen 4.9 kg, Kerosene L.S, Wood (Boiler) 2 kg, Wood (open mass) 8 kg, Wood (patch work) 12 kgBoiler & sprayer 0.04 hr
ii)Over Base course10 m²Unskilled 0.20Bitumen 9.7 kg, Kerosene L.S, Wood (Boiler) 4 kg, Wood (open mass) 16 kg, Wood (patch work) 24 kgBoiler & sprayer 0.04 hr
10. Providing & laying single coat surface dressing including compaction
Single coat surface dressing10 m²Unskilled 0.80Bitumen 34 kg, Kerosene L.S, Wood (Boiler) 8 kg, Wood (open mass) 32 kg, Wood (patch work) 48 kg, 12mm Aggregate 0.15 m³Roller 0.04 hr, Boiler & sprayer 0.04 hr
11. Providing & laying double coat surface dressing
Double coat surface dressing10 m²Unskilled 0.80Bitumen 34 kg, Kerosene L.S, Wood (Boiler) 13 kg, Wood (open mass) 52 kg, Wood (patch work) 78 kg, 12mm Aggregate 0.18 m³, 10mm Aggregate 0.10 m³Roller 0.07 hr, Boiler & sprayer 0.07 hr
12. Providing & semi grouting including compaction
i)5 cm depth10 m²Unskilled 1.20Bitumen 35 kg, Kerosene L.S, Wood 12, 48, 72 kg, 38mm Agg 0.60 m³, 12mm Agg 0.15 m³Roller 0.07 hr, Boiler & sprayer 0.07 hr
ii)10 cm depth10 m²Unskilled 2.00Bitumen 60 kg, Kerosene L.S, Wood 20, 80, 108 kg, 38mm Agg & 12mm Agg (quantity not specified in source)Roller 0.07 hr, Boiler & sprayer 0.07 hr
13. Providing & full grouting including compaction
Full grouting10 m²Unskilled 1.20Bitumen 50 kg, Kerosene L.S, Wood 20, 80, 120 kg, 38mm Agg & 12mm Agg (quantity not specified in source)Roller 0.07 hr, Boiler & sprayer 0.07 hr
14. Providing & laying seal coat including compaction (with 6mm stone chips)
Seal coat10 m²Unskilled 0.45Bitumen 15 kg, Kerosene L.S, Wood 6, 24, 36 kg, 6mm chips 0.12 m³Roller 0.04 hr, Boiler & sprayer 0.04 hr
15. Providing, laying & compaction 40mm thick premixed Asphalt concrete
Premixed Asphalt concrete10 m²Unskilled 0.45Bitumen 9.6 kg, Kerosene L.S, Wood 4, 16, 24 kg, Coarse sand 0.07 m³Roller 0.04 hr, Boiler & sprayer 0.04 hr

Material Rate on the Basis of Government (Ktm – 2071/2072)

S.N.Materials / Manpower / MachineUnitRate (Nrs)Remarks
1Skilled laborno650
2Unskilled laborno475
3Helperno475
4Brick (machine made)no10.92
5Brick (chimney made)no10
6Cement Hetauda-OPC (50 kg)bag743
7Cement Udayapur-OPC (50 kg)bag792
8White cement (40 kg)bag995
9Quarry stonecft561975.68/cum
10River stonecft602116.8/cum
11Quarry sandcft592081.52/cum
12River sandcft622187.36/cum
13. Aggregates (machine-crusher)
6-10 mm sizecft622187.36/cum
10-20 mm sizecft662328.48/cum
20-40 mm sizecft682399.04/cum
6 mm downcft561975.68/cum
Man made (all size)cft612152.08/cum
14. Base course / sub-base course
Gravelcft481693.44/cum
Stone dustcft28987.84/cum
15Wood (Agrakh)cft5400190512/cum
Formwork (mixed)cft114640430.88/cum
16. Reinforcement
8mm diakg82.7
10-25 mm diakg79.7
28mm-32mm diakg82.55
Binding wirekg94
17. Paint
Whitewashkg17
Distemperlit197
Waterproof paintlit420
Enamel paintlit463
Emulsion paintlit464
Aluminiumlit482
Varnishlit389
Chapra polishkg809
Spritlit104
Primer cementkg236
Wood primerlit332
Gumkg231
18. Hinge
3″no15
4″no27
5″no42
6″no55
19. Locking Set
300mmno252
225mmno221
150mmno189
20Tower bolt (3″, 4″, 6″, 8″, 10″, 12″)no20, 39, 65, 78, 91, 103
21. Handle
Ordinaryno31
Specialno46
22Hold fast (7 no/kg)kg121
Nailkg109
2380/100 grade bitumenkg92.6
CRMB-DIGO 55 Bitumenkg99.9
Woodkg17
24White glazed porcelain clay 10 lit cistern complete set (internal part of cistern PVC fittings)set3229.2
25. Super Color Porcelain Pan
580mm size4020
500mm size3090
26White glazed porcelain clay EWC floor mounted commode without cistern, all complete set7854
27Porcelain clay white glaze large flat back urinal 61×41×38 cm size3787
28. Modern Sanitaryware: Mogen, Cotto, Bolan or eqv.
Basin Mixtureset5000
Commodeno13750
Commode seat coverno2200
C.P. 15 mm dia. Angle Valveno1098
C.P. hingeno850
15 mm C.P. Pillar Cock With Aeratorno1115
Flushing pipeno315
Stainless sinkno2250
PVC connectorno290

Rate Analysis Format

S.N. Description Amount
1.Cost of materialX
2.Cost of laborsY
3.Hire of tools and plants (@ 3% of Unskilled labor cost)Z
Sub total (A) =X + Y + Z
4.Contractors overhead and profit @ 15%= 0.15 A
Total (B) =1.15 A
5.VAT @ 13% of Total (B)(Option)
Grand Total =Rate per unit

Note: Extra cost such as scaffolding for super structure etc. may be provided as a L.S. (lump sum) amount.

Solved Rate Analysis Examples

Example 7: Brick work in 1:3 cement mortar for first floor. Unit of analysis per m³.

Volume of brick work = 1.0 m³. Assume brick size = 230mm x 110mm x 55mm; mortar thickness = 10mm; brick size with mortar = 240mm x 120mm x 65mm.

No. of bricks required $= \dfrac{1.0}{0.24 \times 0.120 \times 0.065} = 534.18 \approx 535$ Nos. Add 5% wastage $\therefore$ Brick required $= 1.05 \times 535 = 562$ Nos.

Volume of wet mortar = Total brick work – Actual vol. of brick (without mortar) $= 1 – 534.18 \times (0.23 \times 0.11 \times 0.055) = 0.26\text{ m}^3$

Dry vol. of mortar $= 1.3 \times 0.26 = 0.338\text{ m}^3$. Total part of mix proportion $= 1+3 = 4$.

Required cement $= \dfrac{0.338}{4} = 0.0845\text{ m}^3 = 0.0845 \times 28.8 = 2.434$ bags. Required sand $= 3 \times 0.0845 = 0.2535\text{ m}^3$.

Water cement ratio $= 0.6$; Water $= 0.6 \times 2.434 \times 50 = 73.02$ lit.

Hence, Required: Bricks = 562 no, Cement = 2.434 bag, Sand = 0.2535 m³, Water = 73.02 lit.

S.N.DescriptionUnitQuantityRate (Nrs)Amount
1. Material
i)Cementbag2.4347431808.462
ii)Sandcum0.25352187.36554.4958
iii)Bricksno562105620
iv)Waterlit73.020.2518.255
Sub total (A)8001.213
2. Labors
i)Skilledno1.5650975
ii)Unskilledno2.24751045
iii)Helperno0.7475332.5
Sub total (B)2352.5
Total (A+B)10353.71
3. Hire of tools and plants @ 3% of unskilled labor31.35
Total10385.06
4. Contractors overhead and profit @ 15% of total1557.759
Grand Total11942.82

Hence, Rate per cum = Nrs. 11942.82, excluding VAT

Example 8: 12.5 mm thick cement plaster (1:4) in wall. Unit of rate analysis 100 sqm.

Quantity of plastering work $= 100\text{ m}^2$. Vol. of wet mortar $= 100 \times 0.0125 = 1.25\text{ m}^3$.

Firstly, increase 25% for filling in between joints and irregular surface to get total wet mix $= 1.25 \times 1.25 = 1.5625\text{ m}^3$.

To get dry vol. of mortar, 30% increase: Vol. of dry mortar $= 1.30 \times 1.5625 = 2.031\text{ m}^3$. Total part of mix proportion $= 1+4 = 5$.

Required cement $= \dfrac{1}{5} \times 2.031 = 0.406\text{ m}^3 = 0.406 \times 28.8 = 11.69$ bags. Sand $= 0.406 \times 4 = 1.624\text{ m}^3$.

Water cement ratio $= 0.8$; Water $= 0.8 \times 11.69 \times 50 = 467.71$ lit.

Hence, Required: Cement = 11.69 bag, Sand = 1.624 m³, Water = 467.71 lit.

S.N.DescriptionUnitQuantityRate (Nrs)Amount
1. Material
i)Cementbag11.697438685.67
ii)Sandcum1.6242187.363552.273
iii)Waterlit467.710.25116.9275
Subtotal (A)12354.87
2. Labors
i)Skilledno126507800
ii)Unskilledno164757600
Subtotal (B)15400
Total (A+B)27754.87
3. Hire of tools and plants @ 3% of unskilled labor228
Total27982.87
4. Contractors overhead and profit @ 15% of total4197.431
Grand Total32180.3

Hence, Rate per 100 sqm = Nrs. 32180.3, excluding VAT.

Hence, Rate per sqm = Nrs. 321.8, excluding VAT.

Example 9: PCC (1:2:4). Unit of rate analysis 1 cum.

Total quantity of work (PCC) $= 1.0\text{ m}^3$. To get dry vol. of concrete mix, increase 50% to 55%: Vol. of dry mix $= 1.5 \times 1.0 = 1.5\text{ m}^3$.

Total part of mix proportion $= 1+2+4 = 7$.

Required: Cement $= 1.50 \times \dfrac{1}{7} = 0.214\text{ m}^3 = 0.214 \times 28.8 = 6.16$ bags. Sand $= 0.214 \times 2 = 0.428\text{ m}^3$. Aggregate $= 0.214 \times 4 = 0.856\text{ m}^3$.

Water/Cement $= 0.55$; Water $= 0.55 \times 6.16 \times 50 = 169.94$ lit.

Hence, Required: Cement = 6.16 bag, Sand = 0.428 m³, Aggregate = 0.856 m³, Water = 169.94 lit.

S.N.DescriptionUnitQuantityRate (Nrs)Amount
1. Material
i)Cementbag6.167434576.88
ii)Sandcum0.4282187.36936.1901
iii)Aggregatescum0.8562399.042053.578
iv)Waterlit169.940.2542.485
Subtotal (A)7609.133
2. Labors
i)Skilledno0.8650520
ii)Unskilledno74753325
Subtotal (B)3845
Total (A+B)11454.13
3. Hire of tools and plants @ 3% of unskilled labor99.75
Total11553.88
4. Contractors overhead and profit @ 15% of total1733.082
Grand Total13286.97

Hence, Rate per cum = Nrs. 13286.97, excluding VAT.

Example 10: 10 m³ of stone masonry in 1:6 mortar ratios

Volume of stone masonry $= 10\text{ m}^3$. To get volume of stone, increase by 15% to 20% due to wastage and dressing during placing: Volume of stone $= 10 \times 1.15 = 11.50\text{ m}^3$.

Take volume of dry mortar 30% – 40% of volume of stone masonry due to irregular shape and size of stone available: Vol. of dry mortar $= 40\%$ of work quantity $= 0.4 \times 10 = 4\text{ m}^3$.

Total part of mix proportion $= 1+6 = 7$. Required cement $= \dfrac{1}{7} \times 4 = 0.57\text{ m}^3 = 0.57 \times 28.8 = 16.45$ bags.

Required sand $= 6 \times 0.57 = 3.42\text{ m}^3$. W/C $= 0.6$; Required water $= 0.6 \times 16.45 \times 50 = 493.5$ lit.

S.N.DescriptionUnitQuantityRate (Nrs)Amount
1. Material
i)Cementbag16.4574312222.35
ii)Sandcum3.422187.367480.771
iii)Stonecum11.51975.6822720.32
iv)Waterlit493.50.25123.375
Subtotal (A)42546.82
2. Labors
i)Skilledno156509750
ii)Unskilledno5047523750
Subtotal (B)33500
Total (A+B)76046.82
3. Hire of tools and plants @ 3% of unskilled labor712.5
Total76759.32
4. Contractors overhead and profit @ 15% of total11513.9
Grand TotalNrs. 88273.21

Hence, Rate per 10 cum = Nrs. 88273.21, excluding VAT.

Example 11: Providing, laying & consolidation of 10 cm thick compacted gravel for sub-grade per sqm.

Volume of gravel sub-grade $= \dfrac{10}{100} \times 1 = 0.1\text{ m}^3$. Add 30% – 40% to get loose volume of gravel $= 1.35 \times 0.1 = 0.135\text{ m}^3$.

(A) Materials

i. Well graded gravel $= 0.135\text{ m}^3$ @ Rs 1700 = Rs 229.50

(B) Labors

i. Unskilled $= 0.14$ Nos. @ Rs 475 = Rs 66.50

(C) Equipment

i. Road roller $= 0.028$ hr. @ Rs 1000 = Rs 28.00

(D) Hire of tools and plants $= 3\%$ of unskilled labor cost = Rs 2.00

Total = Rs 326.00

(E) Contractor’s overhead and profit $= 15\%$ of Total $= 0.15 \times 326.00 =$ Rs 48.90

Grand total = Rs 326.00 + Rs 48.90 = Rs 374.90

Hence, Rate per sq. meter = Rs. 374.90

Example 12: Providing and laying 10 cm thick compacted semi grouting per 10 sq.m.

Volume $= 0.1 \times 10 = 1\text{ m}^3$. Loose volume $= 1.4 \times 1 = 1.40\text{ m}^3$.

Materials

i. Well graded Aggregates $= 1.40\text{ m}^3$ @ Rs 2100 = Rs 2940.00

ii. Bitumen $= 60$ kg @ Rs 99.00 = Rs 5940.00

iii. Wood (only boiler) $= 20$ kg @ Rs 17.00 = Rs 340.00

Labors

i. Unskilled $= 2$ Nos. @ Rs 475 = Rs 950.00

Equipment

i. Roller $= 0.07$ hr. @ Rs 1000 = Rs 70.00

ii. Boiler and sprayer $= 0.07$ hr. @ Rs 1000 = Rs 70.00

Hire of tools and plants $= 3\%$ of unskilled labor cost = Rs 28.50

Total = Rs 10310.00

Contractor’s overhead and profit $= 15\%$ of Total $= 0.15 \times 10310.00 =$ Rs 1546.50

Grand total = Rs 10310.00 + Rs 1546.50 = Rs 11856.50

Hence, Rate per 10 sq. meter = Rs. 11856.50

EXample 13:Providing and laying 15mm ɸ GI pipe per rm.

Materials

i. 15 mm dia. GI pipe $= 1$ m @ Rs 250 = Rs 250.00

ii. GI fittings (elbow, bend, tee etc.) = L.S (20-30%) = Rs 75.00

iii. Pipe tape, clamp, screws etc. = L.S (5-7%) = Rs 17.50

Labors

i. Skilled $= 0.18$ Nos. @ Rs 650 = Rs 117.00

ii. Unskilled $= 0.16$ Nos. @ Rs 475 = Rs 76.00

Hire of tools and plants $= 3\%$ of unskilled labor cost = Rs 2.28

Total = Rs 537.78

Contractor’s overhead and profit $= 15\%$ of Total $= 0.15 \times 537.78 =$ Rs 80.67

Grand total = Rs 537.78 + Rs 80.67 = Rs 618.45

Hence, Rate per running meter = Rs 618.45

Example 14: Providing and fixing W.C. commode with low level cistern per no.

(A) MATERIALS

(i) White glazed ceramic clay W.C commode with P or S-trap = 1 no. @ Rs 7854.00 = Rs 7854.00

(ii) White glazed ceramic clay 10 lit. capacity low level cistern with complete accessories = 1 no. @ Rs 3230 = Rs 3230.00

(iii) Commode cover with C.P hinge = 1 no. @ Rs 2200 = Rs 2200.00

(iv) C.P angle valve (Blue star or equivalent) = 1 no. @ Rs 1098 = Rs 1098.00

(v) PVC pipe connector with coupling = 1 no. @ Rs 290 = Rs 290.00

(vi) 32mm dia. PVC flushing pipe with coupling = 1 no. @ Rs 315 = Rs 315.00

(vii) Pipe tape, clamp, screws etc. = L.S = Rs 600.00

Material cost = Rs 15587.00

(B) LABORS

(i) Skilled: 3 no. @ Rs 650 = Rs 1950

(ii) Unskilled: 3 no. @ Rs 475 = Rs 1425

Labor cost = Rs 3375

(C) Hire of tools and plants @ 3% of unskilled labor cost = Rs 42.75

Subtotal = Rs 19004.75

(D) Contractor overhead and profit @ 15% of subtotal = Rs 2850.71

Total = Rs 21855.46 / no

Example 15: Providing and fixing W.C. Pan with low level cistern per no.

(A) MATERIALS

White glazed ceramic clay W.C. Orisa pan with P or S-trap = 1 no. @ Rs 3090.00 = Rs 3090.00

White glazed ceramic clay 10 lit. capacity low level cistern with complete accessories = 1 no. @ Rs 3230 = Rs 3230.00

C.P angle valve (Blue star or equivalent) = 1 no. @ Rs 1098 = Rs 1098.00

PVC pipe connector with coupling = 1 no. @ Rs 290 = Rs 290.00

32mm dia. PVC flushing pipe with coupling = 1 no. @ Rs 315 = Rs 315.00

Pipe tape, clamp, screws etc. = L.S = Rs 600.00

Material cost = Rs 11998.00

(B) LABORS

Skilled: 3 no. @ Rs 650 = Rs 1950

Unskilled: 3 no. @ Rs 475 = Rs 1425

Labor cost = Rs 3375

(C) Hire of tools and plants @ 3% of unskilled labor cost = Rs 42.75

Subtotal = Rs 15415.75

(D) Contractor overhead and profit @ 15% of subtotal = Rs 2312.36

Total = Rs 17758.11 / no

Example 16: Providing and fixing Wash basin per no.

(A) MATERIALS

White glazed ceramic clay 500 x 400 size basin = 1 no. @ Rs………….. = Rs…………….

C.P pillar cock = 1 no. @ Rs………….. = Rs…………….

C.P angle valve (Blue star or equivalent) = 1 no. @ Rs………… = Rs……………

PVC pipe connector with coupling = 1 no. @ Rs………….. = Rs…………..

32mm dia. Waste pipe with coupling = 1 no. @ Rs………… = Rs…………….

Pipe tape, clamp, screws etc. = L.S = Rs……………..

Material cost = Rs……………

(B) LABORS

Skilled: 2 no. @ Rs………… = Rs…………..

Unskilled: 2 no. @ Rs………… = Rs…………..

Labor cost = Rs…………….

(C) Hire of tools and plants @ 3% of unskilled labor cost = Rs…………

Subtotal = Rs……………………

(D) Contractor overhead and profit @ 15% of subtotal = Rs……………….

Total = Rs……………… / no

Road Works Rate Analysis Exercises

Rate for Equipments as per fiscal year 073-74 of Ktm:

  • Loader = 1910/hr (use 1900/hr)
  • Sprayer = 1655/hr (take 1700/hr)
  • Boiler = 1757/hr (take 1800/hr)
  • Grader = 1498/hr (take 1500/hr)
  • Road Roller = 1034/hr (take 1035/hr)
  • Bitumen = 77/kg (take 80/kg)
  • Wood = 20/kg
(i) Providing and Spreading 10 cm Compacted Thickness Approved Sized Gravel in Subgrade (per 10 m²)

Volume of gravel sub-grade $= \dfrac{10}{100} \times 1\text{ m}^2$. Add 30-35% to get loose volume of gravel $= 0.1 + 0.1 \times 0.35 = 0.135\text{ m}^3$.

A) Materials

i) Approved size gravel = 0.135 m³ × Rs…………./m³

B) Labours

i) Unskilled = 0.14 nos. × Rs. 635 per head per day = Rs…………

C) Equipments

i) Road Roller = 0.028 hr × Rs…….. = Rs………..

D) Contractor’s overhead and profit = 15% of (A+B+C) = Rs…………

$\therefore$ Rate per m² = Rs…………..

(ii) Providing, Laying and 10 cm Compacted Thickness Base Course of Crushed Stone (per m²)

i) Vol. of base course $= \dfrac{10}{100} \times 1\text{ m}^2 = 0.1\text{ m}^3$

ii) Add 45-48% to get loose vol. of crushed stone $= 0.1 + \dfrac{48}{100} \times 0.1 = 0.148\text{ m}^3$

A) Materials

i) 75 mm size crushed stone = 0.148 m³ × Rs. ……… = Rs……………

B) Labours

i) Unskilled = 0.15 nos. × Rs. 635 per head per day = Rs………………..

C) Equipments

i) Road Roller = 0.04 hr × Rs…………….. per hour = Rs………………….

D) Contractor’s overhead and profit = 15% of (A+B+C) = Rs………………

$\therefore$ Rate per m² = Rs (A+B+C+D)

(iii) Providing, Laying and Compaction of 5 cm Thick Full Grouting (per 10 m²)

Vol. of 5 cm thick full grouting $= \dfrac{5}{100} \times 10 = 0.5\text{ m}^3$. Add 45-50% to get loose volume $= 0.5 + 0.5 \times 0.5 = 0.75\text{ m}^3$.

A) Materials

i) Bitumen = 50 kg × Rs……………../kg

ii) Kerosene (Lumpsum) = Rs. 100

iii) Wood (20 kg for boiler, 80 kg for open field, 120 kg for patch repairing) × Rs.20 = Rs. 400

B) Labours

i) Unskilled = 1.2 nos. × Rs. 635/head/day = Rs………….

C) Equipments

i) Roller = 0.07 hr × Rs 1035 per hour = Rs. ……………..

ii) Boiler = 0.07 hr × Rs. 1800 per hour = Rs………………

iii) Sprayer = 0.07 hr × Rs. 1700 per hour = Rs……………

Total = Rs…………………

D) Contractor’s overhead and profit = 15% of (A+B+C) = Rs…………

$\therefore$ Rate per 10 m² = Rs……………….

PDF Notes: Analysis of Rate

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