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1. Mendelian Genetics Syllabus

Unit 3: Genetics (this page: chapter 3.2 Mendelian genetics)

3. Genetics
3.1 Genetic Materials: Introduction to genetics and genetic materials, composition, structure and function of DNA and RNA, DNA replication, introduction of genetic code.
3.2 Mendelian genetics: General terminology, Mendel’s experiment and laws of inheritance, gene interactions (incomplete dominance, co-dominance).
3.3 Linkage and crossing over: Concept and types of linkage, sex-linked inheritance (colour blindness in man and eye colour of Drosophila), concept and significances of crossing over.
3.4 Mutation and polyploidy: Concept, type (gene and chromosomal mutation), importance of mutation, polyploidy (origin and significance).

These Mendelian genetics notes follow the NEB Class 12 Biology syllabus (+2 Biology, Nepal), chapter 3.2 of Unit 3 Genetics. Practise the multiple choice questions first, then work through the solved short and long answer questions with the Punnett square figures, and finish with the PDF notes for quick revision.

Mendelian genetics notes - Class 12 Biology NEB Unit 3 Genetics

Figure: Mendelian genetics notes, Class 12 Biology (NEB)

Micro syllabus: 3. Genetics

Define genetics and describe the composition and structure of DNA and RNA.
Describe the mechanism of DNA replication and the concept of the genetic code.
Explain Mendelian genetics, including complete and incomplete dominance.
Explain linkage, crossing over, and sex-linked inheritance.
Describe mutation, its importance, and the concept of polyploidy.

Read more about Mendelian inheritance, Gregor Mendel and the Punnett square on Wikipedia. More notes: Class 12 Biology notes, Class 12 Chemistry notes and Class 12 Physics notes.

2. Mendelian Genetics Notes: Multiple Choice Questions

Question 1. What is a gene?

  • a) A type of cell
  • b) A segment of DNA coding for a protein or RNA
  • c) A chromosome
  • d) An enzyme

Correct Answer: b) A segment of DNA coding for a protein or RNA

Reason: A gene is a small segment of DNA with the instructions for one protein or functional RNA. A chromosome carries many genes.


Question 2. Which of the following is a homozygous genotype?

  • a) Tt
  • b) TT
  • c) XY
  • d) TX

Correct Answer: b) TT

Reason: Homozygous means two identical alleles (TT or tt). Tt has two different alleles, so it is heterozygous.


Question 3. Which term refers to the physical appearance of an individual?

  • a) Genotype
  • b) Phenotype
  • c) Allele
  • d) Trait

Correct Answer: b) Phenotype

Reason: Phenotype is the visible expression of the genotype and the environment. Genotype is the genetic make-up.


Question 4. In the dihybrid cross (TTRR × ttrr), which gametes are produced by the F₁ plants?

  • a) TR and tr only
  • b) Tt and Rr
  • c) TR, Tr, tR, tr
  • d) TT, tt, RR, rr

Correct Answer: c) TR, Tr, tR, tr

Reason: F₁ plants are TtRr. By independent assortment they make four gametes in equal numbers: TR, Tr, tR and tr.


Question 5. Why do the recessive traits reappear in the F₂ generation after being hidden in the F₁ generation?

  • a) Due to the dominance of the recessive allele
  • b) Because they mutate back
  • c) Because of segregation and recombination of alleles
  • d) Because blending occurs in the F₁ generation

Correct Answer: c) Because of segregation and recombination of alleles

Reason: Alleles stay unchanged in F₁ and separate in gametes. In F₂ two recessive alleles can meet again (tt).

Question 6. In pea plants, yellow seeds are dominant to green. If a heterozygous yellow-seeded plant is crossed with a green-seeded plant, what ratio of yellow and green-seeded plants would you expect in the F₁ generation?

  • a) 9:1
  • b) 1:3
  • c) 3:1
  • d) 50:50

Correct Answer: d) 50:50

Reason: Yy × yy gives 1 Yy (yellow) : 1 yy (green), which is 50 : 50. A 3 : 1 ratio comes from Yy × Yy.


Question 7. A geneticist notices that a trait appears intermediate in hybrids, but original traits reappear in the F₂ generation. What inheritance pattern is likely?

  • a) Complete dominance
  • b) Incomplete dominance
  • c) Co-dominance
  • d) Polygenic inheritance

Correct Answer: b) Incomplete dominance

Reason: In incomplete dominance the hybrid is a blend of both parents and the parental types return in F₂ in the ratio 1 : 2 : 1.


Question 8. If a red-flowered Mirabilis jalapa plant is crossed with a pink-flowered plant, what will be the expected flower colour ratio in the offspring?

  • a) 1 red : 1 white
  • b) 1 red : 1 pink
  • c) 1 red : 2 pink : 1 white
  • d) All pink

Correct Answer: b) 1 red : 1 pink

Reason: Red (RR) × pink (RW) gives 1 RR (red) : 1 RW (pink). The 1 : 2 : 1 ratio comes from pink × pink.


Question 9. Which of the following crosses will give tall and dwarf pea plants in the same proportions?

  • a) TT × tt
  • b) Tt × tt
  • c) TT × Tt
  • d) tt × tt

Correct Answer: b) Tt × tt

Reason: Tt × tt is a test cross. It gives 1 Tt (tall) : 1 tt (dwarf). TT × tt gives all tall.


Question 10. Round seed trait (R) is dominant over wrinkled (r) seed trait in pea. A heterozygous round seeded plant (Rr) is crossed with a wrinkled seeded plant (rr). What is the possible progeny?

  • a) 302 round : 102 wrinkled
  • b) 210 round : 95 wrinkled
  • c) 105 round : 99 wrinkled
  • d) 103 round : 315 wrinkled

Correct Answer: c) 105 round : 99 wrinkled

Reason: Rr × rr is a test cross with the expected ratio 1 : 1. Only 105 : 99 is close to 1 : 1.

3. Mendelian Genetics Notes: Short and Long Answer Questions

Mendelian Genetics Notes: Short Answer Questions

Q.1 Define recessive character and dominant character.

Dominant character: In a cross between two pure parents with contrasting characters, the character that appears in the F₁ generation is the dominant character. It is expressed even when only one copy of its allele is present (TT and Tt). Example: tallness (T) in pea plants.

Recessive character: The character that stays hidden (suppressed) in the F₁ generation is the recessive character. It is expressed only when two copies of its allele are present (tt). Example: dwarfness (t) in pea plants.


Q.2 What are the genotype and phenotype of F₁ generation in a monohybrid cross between TT and tt plants?
Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generationParents (P)GametesF₁ generationF₁ gametesF₂ generationPure tall plantPure dwarf plantTTttTtTt100% hybrid tallTtSelfing: Tt × TtTtTtTTTtTtttPhenotypic ratio: 3 tall : 1 dwarfGenotypic ratio: 1 TT : 2 Tt : 1 tt

Figure: Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generation

Genotype: all F₁ plants are Tt (heterozygous). T comes from the tall parent and t from the dwarf parent.
Phenotype: all F₁ plants are tall (100% hybrid tall), because T is dominant over t.

Q.3 Arrange these in order of size, smallest first: Cell, Nucleus, DNA molecules, Chromosome, Gene

Gene → DNA molecule → Chromosome → Nucleus → Cell

A gene is a small segment of a DNA molecule.
A DNA molecule is a long chain that carries many genes.
A chromosome is DNA coiled with proteins.
The nucleus holds all the chromosomes of the cell.
The cell contains the nucleus, so it is the largest.
Q.4 Differentiate between monohybrid and dihybrid cross.
Monohybrid crossDihybrid cross
Cross between parents differing in one pair of contrasting characters.Cross between parents differing in two pairs of contrasting characters.
Example: TT × tt (height).Example: TTRR × ttrr (height and flower colour).
F₁ hybrid forms 2 types of gametes (T and t).F₁ hybrid forms 4 types of gametes (TR, Tr, tR, tr).
F₂ phenotypic ratio is 3 : 1.F₂ phenotypic ratio is 9 : 3 : 3 : 1.
F₂ genotypic ratio is 1 : 2 : 1.F₂ genotypic ratio is 1 : 2 : 2 : 4 : 1 : 2 : 1 : 2 : 1.
Gives the law of segregation.Gives the law of independent assortment.

Q.5 How is incomplete dominance different from Mendel’s law of dominance?
Incomplete dominance in Mirabilis jalapa (four o’clock plant): red × white gives pink in F₁ and 1:2:1 in F₂Parents (P)GametesF₁ generationF₂ generationRed RRWhite WWRWPink RW100% pink (intermediate)Selfing RW × RWRWRWRRRWRWWW1 red : 2 pink : 1 white (both ratios 1:2:1)Genotypic ratio 1 RR : 2 RW : 1 WW

Figure: Incomplete dominance in Mirabilis jalapa (four o’clock plant): red × white gives pink in F₁ and 1:2:1 in F₂

Mendel’s law of dominanceIncomplete dominance
One allele fully hides the other in the hybrid.Neither allele is fully dominant.
F₁ hybrid looks like the dominant parent.F₁ hybrid is intermediate between the two parents.
F₂ phenotypic ratio is 3 : 1.F₂ phenotypic ratio is 1 : 2 : 1.
Example: tall × dwarf pea gives all tall.Example: red × white Mirabilis jalapa gives all pink.

Q.6 Why is blood group AB considered an example of co-dominance?
Co-dominance in human ABO blood group: IᴬIᴬ × IᴮIᴮ gives IᴬIᴮ (blood group AB)ParentsGenotypeGametesF₁ generationBlood group ABlood group BIAIAIBIBABIAIBIAIBBlood group ABBoth antigens A and B are present

Figure: Co-dominance in human ABO blood group: IᴬIᴬ × IᴮIᴮ gives IᴬIᴮ (blood group AB)

In blood group AB the person has the alleles Iᴬ and Iᴮ. Iᴬ makes antigen A and Iᴮ makes antigen B. Neither allele hides the other and neither blends with it, so both are fully expressed at the same time and both antigens are found in the blood. Both alleles are expressed equally in the F₁ hybrid, which is the meaning of co-dominance. Cross: IᴬIᴬ (group A) × IᴮIᴮ (group B) gives IᴬIᴮ (group AB).


Q.7 State Mendel’s law of dominance with an example.
Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generationParents (P)GametesF₁ generationF₁ gametesF₂ generationPure tall plantPure dwarf plantTTttTtTt100% hybrid tallTtSelfing: Tt × TtTtTtTTTtTtttPhenotypic ratio: 3 tall : 1 dwarfGenotypic ratio: 1 TT : 2 Tt : 1 tt

Figure: Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generation

Law of dominance: When two pure organisms having a pair of contrasting characters are crossed, only one character of the pair appears in the F₁ generation while the other remains hidden. The character that appears is dominant and the hidden one is recessive.

Example: A pure tall pea plant (TT) crossed with a pure dwarf plant (tt) gives all tall plants (Tt) in F₁. So tallness is dominant and dwarfness is recessive.

Q.8 Why did Mendel choose pea plants for his experiments?

Mendel chose the garden pea (Pisum sativum) because:

It has several pairs of clearly contrasting traits (tall/dwarf, round/wrinkled seeds).
Flowers are naturally self-pollinating, as the stamens and pistil are enclosed in the petals.
Cross-pollination is easy to do by hand, so he could control the parents.
It has a short life cycle, so many generations can be studied quickly.
It is easy to grow in pots or in the garden.
Each plant gives a large number of seeds, which gives plenty of data.
The hybrids are fertile.

The seven pairs of contrasting characters he studied:

CharacterDominantRecessive
Seed shapeRoundWrinkled
Seed colourYellowGreen
Pod shapeInflatedConstricted
Pod colourGreenYellow
Flower colourPurple (red)White
Flower positionAxialTerminal
Plant heightTallDwarf

Q.9 In a species of plant, there are two alleles of the gene that determines leaf shape. One allele produces round leaves, and the other produces oval leaves. Heterozygous plants have round leaves. Which allele is dominant? Explain.

The allele for round leaves is dominant.

Explanation: A heterozygous plant has one allele for round and one for oval leaves. Only the round shape appears, so the round allele hides the effect of the oval allele. This is Mendel’s law of dominance: the allele that is expressed in the heterozygote is dominant and the hidden one is recessive. The oval allele will show only in plants with two copies of it.


Q.10 A student observes a 9:3:3:1 ratio in the offspring of a cross. What type of cross has been performed and which of Mendel’s law does it demonstrate?
Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square)Parents (P)GametesF₁ generationF₁ gametesTall, red flowerDwarf, white flowerTTRRttrrTRtrTtRr100% tall with red flowersTRTrtRtrF₁ × F₁ (selfing): F₂ generationTRTrtRtrTRTrtRtrTTRRTTRrTtRRTtRrTTRrTTrrTtRrTtrrTtRRTtRrttRRttRrTtRrTtrrttRrttrr9 tall, red3 tall, white3 dwarf, red1 dwarf, whitePhenotypic ratio 9 : 3 : 3 : 1Genotypic ratio 1:2:2:4:1:2:1:2:1

Figure: Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square)

Type of cross: a dihybrid cross between two plants that are both heterozygous for two traits (for example TtRr × TtRr, the selfing of the F₁ plants).
Law demonstrated: Mendel’s law of independent assortment. The alleles of the two genes separate into gametes independently, so new combinations such as tall white and dwarf red appear in the 9 : 3 : 3 : 1 ratio.

Mendelian Genetics Notes: Long Answer Questions

Q.1 Describe Mendel’s law of independent assortment with the help of a dihybrid cross.
Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square)Parents (P)GametesF₁ generationF₁ gametesTall, red flowerDwarf, white flowerTTRRttrrTRtrTtRr100% tall with red flowersTRTrtRtrF₁ × F₁ (selfing): F₂ generationTRTrtRtrTRTrtRtrTTRRTTRrTtRRTtRrTTRrTTrrTtRrTtrrTtRRTtRrttRRttRrTtRrTtrrttRrttrr9 tall, red3 tall, white3 dwarf, red1 dwarf, whitePhenotypic ratio 9 : 3 : 3 : 1Genotypic ratio 1:2:2:4:1:2:1:2:1

Figure: Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square)

Law of independent assortment: When two or more pairs of contrasting alleles are inherited together, the inheritance of one pair occurs independently of the other. The alleles of different genes assort into gametes randomly and independently.

Dihybrid cross (height and flower colour):

P generation: pure tall with red flowers (TTRR) × pure dwarf with white flowers (ttrr).
Gametes: TR and tr.
F₁ generation: all TtRr, tall with red flowers.
F₁ gametes: four types in equal numbers, TR, Tr, tR and tr, because T and t separate independently of R and r.
F₂ generation: selfing of F₁ plants gives 16 combinations in the Punnett square:
PhenotypeNumberGenotypes
Tall, red9TTRR, TTRr, TtRR, TtRr
Tall, white3TTrr, Ttrr
Dwarf, red3ttRR, ttRr
Dwarf, white1ttrr

Phenotypic ratio = 9 : 3 : 3 : 1. Genotypic ratio = 1 : 2 : 2 : 4 : 1 : 2 : 1 : 2 : 1.

Conclusion: The new combinations tall white and dwarf red, which were not in the parents, show that the gene for height is not linked with the gene for flower colour. They assort independently.


Q.2 If a tall plant with red flowers (TtRr) is self-pollinated, what are the chances of obtaining a dwarf plant with white flowers in F₂ generation? Show using a Punnett square.
Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square), ttrr box markedParents (P)GametesF₁ generationF₁ gametesTall, red flowerDwarf, white flowerTTRRttrrTRtrTtRr100% tall with red flowersTRTrtRtrF₁ × F₁ (selfing): F₂ generationTRTrtRtrTRTrtRtrTTRRTTRrTtRRTtRrTTRrTTrrTtRrTtrrTtRRTtRrttRRttRrTtRrTtrrttRrttrr9 tall, red3 tall, white3 dwarf, red1 dwarf, whitePhenotypic ratio 9 : 3 : 3 : 1Genotypic ratio 1:2:2:4:1:2:1:2:1

Figure: Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square), ttrr box marked

Cross: TtRr × TtRr
Gametes of each parent: TR, Tr, tR, tr (each 1/4).
Required offspring: dwarf with white flowers = ttrr.

The Punnett square below has 16 boxes. The ttrr genotype is found in only one box (marked in red), when a tr egg meets a tr pollen grain.

Chance = 1/4 × 1/4 = 1/16 (6.25%).

The full F₂ ratio is 9 tall red : 3 tall white : 3 dwarf red : 1 dwarf white.


Q.3 In human beings blue eye colour is recessive to brown eye colour. A brown eyed man has a blue eyed mother.
Cross Bb × bb (brown-eyed man × blue-eyed woman)Man: Bb (brown eyes) × Woman: bb (blue eyes)bbBbBbBbbbbbOffspring: 50% Bb (brown eyes) : 50% bb (blue eyes)brownblue

Figure: Cross Bb × bb (brown-eyed man × blue-eyed woman)

Let B = brown (dominant) and b = blue (recessive).

a. What is the genotype of the man and his mother?

Mother: blue-eyed, so she is homozygous recessive, bb.
Man: brown-eyed, so he has at least one B. He must get one b from his blue-eyed mother, so he is Bb.

b. What are the possible genotypes of his father?

The man got b from his mother, so he got B from his father. The father has at least one B. He may be BB or Bb (both brown-eyed).

c. If the man marries a blue eyed woman, what are the possible genotypes of their offspring?

Man Bb (gametes B and b) × woman bb (gametes b only). Offspring: 50% Bb (brown eyes) and 50% bb (blue eyes), a 1 : 1 ratio.


Q.4 A pure breeding (homozygous) tall pea plant was crossed with a homozygous dwarf pea plant. All of the offspring had the genotype Tt. Several of these offspring were crossed together. There are 302 tall plants and 99 plants were dwarf. Construct a complete genetic diagram to explain this result.
Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generationParents (P)GametesF₁ generationF₁ gametesF₂ generationPure tall plantPure dwarf plantTTttTtTt100% hybrid tallTtSelfing: Tt × TtTtTtTTTtTtttPhenotypic ratio: 3 tall : 1 dwarfGenotypic ratio: 1 TT : 2 Tt : 1 tt

Figure: Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generation

P generation: pure tall (TT) × pure dwarf (tt). Gametes: T and t.
F₁ generation: all Tt, all tall.
F₁ × F₁: Tt × Tt. Gametes: T, t and T, t.
F₂ generation: 1 TT : 2 Tt : 1 tt (see the Punnett square in the figure).

Phenotypic ratio = 3 tall : 1 dwarf. Genotypic ratio = 1 : 2 : 1.

Explanation of the result: Total plants = 302 + 99 = 401. For a 3 : 1 ratio the expected numbers are 3/4 × 401 ≈ 301 tall and 1/4 × 401 ≈ 100 dwarf. The observed 302 tall : 99 dwarf is very close to 3 : 1, so the result agrees with Mendel’s law of segregation.


Q.5 Study the table and answer the following questions:
GametesRYrYRyry
RYRRYYRrYYRRYyRrYy
rYRrYYrrYYRrYyrrYy
RyRRYyRrYyRRyyRryy
ryRrYyrrYyRryyrryy

a. Name the dominant and recessive traits.

In this standard cross (R = round, Y = yellow), the dominant traits are round seed (R) and yellow seed (Y). The recessive traits are wrinkled seed (r) and green seed (y). A capital letter stands for the dominant allele and a small letter for the recessive allele.

b. What was the parent genotype if the table shows F₂ generation?

The table has 16 boxes and four types of gametes on each side, so the parents of this cross were F₁ plants heterozygous for both genes: RrYy × RrYy. These F₁ plants came from RRYY × rryy.

c. What is the F₂ phenotype ratio?

Counting the 16 boxes gives 9 round yellow (R_Y_), 3 round green (R_yy), 3 wrinkled yellow (rrY_) and 1 wrinkled green (rryy). The F₂ phenotypic ratio is 9 : 3 : 3 : 1.

4. Mendelian Genetics Notes PDF

PDF Notes 1: Genetics (Unit 3)

PDF Notes 2: Mendelian Genetics (Chapter 3.2)

5. Mendelian Genetics: Frequently Asked Questions

What is Mendelian genetics? (Mendelian genetics notes)
Mendelian genetics is the study of how traits are passed from parents to offspring according to the laws given by Gregor Mendel from his work on garden pea (Pisum sativum). It is chapter 3.2 of Unit 3 Genetics in Class 12 Biology (NEB).
What are Mendel’s three laws of inheritance?
The law of dominance, the law of segregation (purity of gametes) and the law of independent assortment.
Why is Mendel called the father of genetics?
Mendel worked on pea plants for seven years, presented his results in 1865 and was the first to state the principles of heredity. His work was rediscovered in 1900 by De Vries, Correns and Tschermak.
What is the phenotypic ratio of a monohybrid cross?
The F₂ phenotypic ratio of a monohybrid cross is 3 : 1 (tall : dwarf) and the genotypic ratio is 1 : 2 : 1.
What is the phenotypic ratio of a dihybrid cross?
The F₂ phenotypic ratio of a dihybrid cross is 9 : 3 : 3 : 1 and the genotypic ratio is 1 : 2 : 2 : 4 : 1 : 2 : 1 : 2 : 1.
What is a Punnett square?
A Punnett square is a checkerboard method to show all possible results of a cross. Male gametes are placed along the top and female gametes along the side, and the boxes are filled by combining them.
What is incomplete dominance? Give an example.
In incomplete dominance neither allele is completely dominant, so the hybrid is intermediate between the parents. Red × white Mirabilis jalapa gives pink F₁ and a 1 : 2 : 1 ratio in F₂.
What is co-dominance? Give an example.
In co-dominance both alleles are fully expressed in the hybrid. Human blood group AB (IᴬIᴮ) is the best example.
What is the difference between genotype and phenotype?
Genotype is the genetic make-up of an organism (for example Tt). Phenotype is its visible appearance (for example tall).
What is the difference between homozygous and heterozygous?
A homozygous organism has two identical alleles (TT or tt). A heterozygous organism has two different alleles (Tt).
Where can I download Mendelian genetics notes PDF for Class 12 Biology?
You can view and download the PDF notes in the View PDF section of this page. It has the Genetics unit notes and the Mendelian Genetics chapter notes.
Is this Class 12 Biology book PDF for Nepal NEB?
Yes. These notes follow the NEB Class 12 Biology syllabus of Nepal and the Asmita Publication textbook, Unit 3 Genetics.

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