Mendelian Genetics Notes
Class 12 Biology Notes • NEB Syllabus 2083
Mendelian genetics notes for Class 12 Biology Unit 3 chapter 3.2: syllabus, micro syllabus, 10 solved multiple choice questions, all short and long answer questions with Punnett square figures on Mendel’s laws, monohybrid and dihybrid crosses, incomplete dominance and co-dominance, and two PDF notes.
1. Mendelian Genetics Syllabus
Unit 3: Genetics (this page: chapter 3.2 Mendelian genetics)
These Mendelian genetics notes follow the NEB Class 12 Biology syllabus (+2 Biology, Nepal), chapter 3.2 of Unit 3 Genetics. Practise the multiple choice questions first, then work through the solved short and long answer questions with the Punnett square figures, and finish with the PDF notes for quick revision.

Figure: Mendelian genetics notes, Class 12 Biology (NEB)
Micro syllabus: 3. Genetics
Read more about Mendelian inheritance, Gregor Mendel and the Punnett square on Wikipedia. More notes: Class 12 Biology notes, Class 12 Chemistry notes and Class 12 Physics notes.
2. Mendelian Genetics Notes: Multiple Choice Questions
Question 1. What is a gene?
- a) A type of cell
- b) A segment of DNA coding for a protein or RNA
- c) A chromosome
- d) An enzyme
Correct Answer: b) A segment of DNA coding for a protein or RNA
Reason: A gene is a small segment of DNA with the instructions for one protein or functional RNA. A chromosome carries many genes.
Question 2. Which of the following is a homozygous genotype?
- a) Tt
- b) TT
- c) XY
- d) TX
Correct Answer: b) TT
Reason: Homozygous means two identical alleles (TT or tt). Tt has two different alleles, so it is heterozygous.
Question 3. Which term refers to the physical appearance of an individual?
- a) Genotype
- b) Phenotype
- c) Allele
- d) Trait
Correct Answer: b) Phenotype
Reason: Phenotype is the visible expression of the genotype and the environment. Genotype is the genetic make-up.
Question 4. In the dihybrid cross (TTRR × ttrr), which gametes are produced by the F₁ plants?
- a) TR and tr only
- b) Tt and Rr
- c) TR, Tr, tR, tr
- d) TT, tt, RR, rr
Correct Answer: c) TR, Tr, tR, tr
Reason: F₁ plants are TtRr. By independent assortment they make four gametes in equal numbers: TR, Tr, tR and tr.
Question 5. Why do the recessive traits reappear in the F₂ generation after being hidden in the F₁ generation?
- a) Due to the dominance of the recessive allele
- b) Because they mutate back
- c) Because of segregation and recombination of alleles
- d) Because blending occurs in the F₁ generation
Correct Answer: c) Because of segregation and recombination of alleles
Reason: Alleles stay unchanged in F₁ and separate in gametes. In F₂ two recessive alleles can meet again (tt).
Question 6. In pea plants, yellow seeds are dominant to green. If a heterozygous yellow-seeded plant is crossed with a green-seeded plant, what ratio of yellow and green-seeded plants would you expect in the F₁ generation?
- a) 9:1
- b) 1:3
- c) 3:1
- d) 50:50
Correct Answer: d) 50:50
Reason: Yy × yy gives 1 Yy (yellow) : 1 yy (green), which is 50 : 50. A 3 : 1 ratio comes from Yy × Yy.
Question 7. A geneticist notices that a trait appears intermediate in hybrids, but original traits reappear in the F₂ generation. What inheritance pattern is likely?
- a) Complete dominance
- b) Incomplete dominance
- c) Co-dominance
- d) Polygenic inheritance
Correct Answer: b) Incomplete dominance
Reason: In incomplete dominance the hybrid is a blend of both parents and the parental types return in F₂ in the ratio 1 : 2 : 1.
Question 8. If a red-flowered Mirabilis jalapa plant is crossed with a pink-flowered plant, what will be the expected flower colour ratio in the offspring?
- a) 1 red : 1 white
- b) 1 red : 1 pink
- c) 1 red : 2 pink : 1 white
- d) All pink
Correct Answer: b) 1 red : 1 pink
Reason: Red (RR) × pink (RW) gives 1 RR (red) : 1 RW (pink). The 1 : 2 : 1 ratio comes from pink × pink.
Question 9. Which of the following crosses will give tall and dwarf pea plants in the same proportions?
- a) TT × tt
- b) Tt × tt
- c) TT × Tt
- d) tt × tt
Correct Answer: b) Tt × tt
Reason: Tt × tt is a test cross. It gives 1 Tt (tall) : 1 tt (dwarf). TT × tt gives all tall.
Question 10. Round seed trait (R) is dominant over wrinkled (r) seed trait in pea. A heterozygous round seeded plant (Rr) is crossed with a wrinkled seeded plant (rr). What is the possible progeny?
- a) 302 round : 102 wrinkled
- b) 210 round : 95 wrinkled
- c) 105 round : 99 wrinkled
- d) 103 round : 315 wrinkled
Correct Answer: c) 105 round : 99 wrinkled
Reason: Rr × rr is a test cross with the expected ratio 1 : 1. Only 105 : 99 is close to 1 : 1.
3. Mendelian Genetics Notes: Short and Long Answer Questions
Mendelian Genetics Notes: Short Answer Questions
Dominant character: In a cross between two pure parents with contrasting characters, the character that appears in the F₁ generation is the dominant character. It is expressed even when only one copy of its allele is present (TT and Tt). Example: tallness (T) in pea plants.
Recessive character: The character that stays hidden (suppressed) in the F₁ generation is the recessive character. It is expressed only when two copies of its allele are present (tt). Example: dwarfness (t) in pea plants.
Figure: Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generation
Gene → DNA molecule → Chromosome → Nucleus → Cell
| Monohybrid cross | Dihybrid cross |
|---|---|
| Cross between parents differing in one pair of contrasting characters. | Cross between parents differing in two pairs of contrasting characters. |
| Example: TT × tt (height). | Example: TTRR × ttrr (height and flower colour). |
| F₁ hybrid forms 2 types of gametes (T and t). | F₁ hybrid forms 4 types of gametes (TR, Tr, tR, tr). |
| F₂ phenotypic ratio is 3 : 1. | F₂ phenotypic ratio is 9 : 3 : 3 : 1. |
| F₂ genotypic ratio is 1 : 2 : 1. | F₂ genotypic ratio is 1 : 2 : 2 : 4 : 1 : 2 : 1 : 2 : 1. |
| Gives the law of segregation. | Gives the law of independent assortment. |
Figure: Incomplete dominance in Mirabilis jalapa (four o’clock plant): red × white gives pink in F₁ and 1:2:1 in F₂
| Mendel’s law of dominance | Incomplete dominance |
|---|---|
| One allele fully hides the other in the hybrid. | Neither allele is fully dominant. |
| F₁ hybrid looks like the dominant parent. | F₁ hybrid is intermediate between the two parents. |
| F₂ phenotypic ratio is 3 : 1. | F₂ phenotypic ratio is 1 : 2 : 1. |
| Example: tall × dwarf pea gives all tall. | Example: red × white Mirabilis jalapa gives all pink. |
Figure: Co-dominance in human ABO blood group: IᴬIᴬ × IᴮIᴮ gives IᴬIᴮ (blood group AB)
In blood group AB the person has the alleles Iᴬ and Iᴮ. Iᴬ makes antigen A and Iᴮ makes antigen B. Neither allele hides the other and neither blends with it, so both are fully expressed at the same time and both antigens are found in the blood. Both alleles are expressed equally in the F₁ hybrid, which is the meaning of co-dominance. Cross: IᴬIᴬ (group A) × IᴮIᴮ (group B) gives IᴬIᴮ (group AB).
Figure: Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generation
Law of dominance: When two pure organisms having a pair of contrasting characters are crossed, only one character of the pair appears in the F₁ generation while the other remains hidden. The character that appears is dominant and the hidden one is recessive.
Example: A pure tall pea plant (TT) crossed with a pure dwarf plant (tt) gives all tall plants (Tt) in F₁. So tallness is dominant and dwarfness is recessive.
Mendel chose the garden pea (Pisum sativum) because:
The seven pairs of contrasting characters he studied:
| Character | Dominant | Recessive |
|---|---|---|
| Seed shape | Round | Wrinkled |
| Seed colour | Yellow | Green |
| Pod shape | Inflated | Constricted |
| Pod colour | Green | Yellow |
| Flower colour | Purple (red) | White |
| Flower position | Axial | Terminal |
| Plant height | Tall | Dwarf |
The allele for round leaves is dominant.
Explanation: A heterozygous plant has one allele for round and one for oval leaves. Only the round shape appears, so the round allele hides the effect of the oval allele. This is Mendel’s law of dominance: the allele that is expressed in the heterozygote is dominant and the hidden one is recessive. The oval allele will show only in plants with two copies of it.
Figure: Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square)
Mendelian Genetics Notes: Long Answer Questions
Figure: Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square)
Law of independent assortment: When two or more pairs of contrasting alleles are inherited together, the inheritance of one pair occurs independently of the other. The alleles of different genes assort into gametes randomly and independently.
Dihybrid cross (height and flower colour):
| Phenotype | Number | Genotypes |
|---|---|---|
| Tall, red | 9 | TTRR, TTRr, TtRR, TtRr |
| Tall, white | 3 | TTrr, Ttrr |
| Dwarf, red | 3 | ttRR, ttRr |
| Dwarf, white | 1 | ttrr |
Phenotypic ratio = 9 : 3 : 3 : 1. Genotypic ratio = 1 : 2 : 2 : 4 : 1 : 2 : 1 : 2 : 1.
Conclusion: The new combinations tall white and dwarf red, which were not in the parents, show that the gene for height is not linked with the gene for flower colour. They assort independently.
Figure: Dihybrid cross between TTRR and ttrr pea plants up to F₂ generation (Punnett square), ttrr box marked
The Punnett square below has 16 boxes. The ttrr genotype is found in only one box (marked in red), when a tr egg meets a tr pollen grain.
Chance = 1/4 × 1/4 = 1/16 (6.25%).
The full F₂ ratio is 9 tall red : 3 tall white : 3 dwarf red : 1 dwarf white.
Figure: Cross Bb × bb (brown-eyed man × blue-eyed woman)
Let B = brown (dominant) and b = blue (recessive).
a. What is the genotype of the man and his mother?
b. What are the possible genotypes of his father?
The man got b from his mother, so he got B from his father. The father has at least one B. He may be BB or Bb (both brown-eyed).
c. If the man marries a blue eyed woman, what are the possible genotypes of their offspring?
Man Bb (gametes B and b) × woman bb (gametes b only). Offspring: 50% Bb (brown eyes) and 50% bb (blue eyes), a 1 : 1 ratio.
Figure: Monohybrid cross between pure tall (TT) and pure dwarf (tt) pea plants up to F₂ generation
Phenotypic ratio = 3 tall : 1 dwarf. Genotypic ratio = 1 : 2 : 1.
Explanation of the result: Total plants = 302 + 99 = 401. For a 3 : 1 ratio the expected numbers are 3/4 × 401 ≈ 301 tall and 1/4 × 401 ≈ 100 dwarf. The observed 302 tall : 99 dwarf is very close to 3 : 1, so the result agrees with Mendel’s law of segregation.
| Gametes | RY | rY | Ry | ry |
|---|---|---|---|---|
| RY | RRYY | RrYY | RRYy | RrYy |
| rY | RrYY | rrYY | RrYy | rrYy |
| Ry | RRYy | RrYy | RRyy | Rryy |
| ry | RrYy | rrYy | Rryy | rryy |
a. Name the dominant and recessive traits.
In this standard cross (R = round, Y = yellow), the dominant traits are round seed (R) and yellow seed (Y). The recessive traits are wrinkled seed (r) and green seed (y). A capital letter stands for the dominant allele and a small letter for the recessive allele.
b. What was the parent genotype if the table shows F₂ generation?
The table has 16 boxes and four types of gametes on each side, so the parents of this cross were F₁ plants heterozygous for both genes: RrYy × RrYy. These F₁ plants came from RRYY × rryy.
c. What is the F₂ phenotype ratio?
Counting the 16 boxes gives 9 round yellow (R_Y_), 3 round green (R_yy), 3 wrinkled yellow (rrY_) and 1 wrinkled green (rryy). The F₂ phenotypic ratio is 9 : 3 : 3 : 1.
4. Mendelian Genetics Notes PDF
PDF Notes 1: Genetics (Unit 3)
PDF Notes 2: Mendelian Genetics (Chapter 3.2)
5. Mendelian Genetics: Frequently Asked Questions
What is Mendelian genetics? (Mendelian genetics notes)
What are Mendel’s three laws of inheritance?
Why is Mendel called the father of genetics?
What is the phenotypic ratio of a monohybrid cross?
What is the phenotypic ratio of a dihybrid cross?
What is a Punnett square?
What is incomplete dominance? Give an example.
What is co-dominance? Give an example.
What is the difference between genotype and phenotype?
What is the difference between homozygous and heterozygous?
Where can I download Mendelian genetics notes PDF for Class 12 Biology?
Is this Class 12 Biology book PDF for Nepal NEB?
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