Class 12 Physics Chapter 22: Semiconductor Devices Notes (NEB New Syllabus) | P-N Junction, Diode Characteristics, Full-Wave Rectifier, Logic Gates, Numerical Problems & Solutions | Semiconductor PDF
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1. Syllabus

Unit: Modern Physics

Chapter 22: Semiconductor Devices (6 hours)

22.1 P-N junction
22.2 Semiconductor diode: characteristics in forward and reverse bias
22.3 Full-wave rectification
22.4 Logic gates: NOT, OR, AND, NAND and NOR

These notes follow the NEB Class 12 Physics syllabus (+2 Physics, Nepal). Practise the multiple choice questions first, then work through the numericals, and finish with the PDF notes for quick revision.

2. Multiple Choice Questions

Question 1. Barrier potential difference is the potential difference across:

  • a) terminals of a cell
  • b) depletion layer of a p-n junction
  • c) capacitor plates
  • d) ends of a conductor

Correct Answer: b) depletion layer of a p-n junction

Reason: Electrons diffuse from the n-side to the p-side and holes from the p-side to the n-side. This leaves uncompensated positive donor ions on the n-side and negative acceptor ions on the p-side. This region is the depletion layer, and the potential difference set up across it by these fixed ions is the barrier potential difference.


Question 2. The current through a p-n junction is negligible when the junction is:

  • a) forward biased
  • b) reverse biased
  • c) positive biased
  • d) negative biased

Correct Answer: b) reverse biased

Reason: In reverse bias the applied voltage widens the depletion layer and raises the barrier, so majority carriers cannot cross. Only a very small leakage current of thermally generated minority carriers flows.


Question 3. A reverse biased p-n junction has:

  • a) very narrow depletion layer
  • b) almost no current
  • c) very low resistance
  • d) large current flow

Correct Answer: b) almost no current

Reason: Reverse bias widens the depletion layer and increases the potential barrier. The junction then has very high resistance and only a tiny reverse saturation current flows, so there is almost no current.


Question 4. Which device is used to convert alternating current into direct current?

  • a) transformer
  • b) rectifier
  • c) diode
  • d) triode

Correct Answer: b) rectifier

Reason: A rectifier is the device (circuit) that converts alternating current, which reverses direction periodically, into direct current, which flows in one direction only. Diodes are the components from which a rectifier is built.

Question 5. A Zener diode can be used as a:

  • a) rectifier
  • b) voltage regulator
  • c) oscillator
  • d) voltage divider

Correct Answer: b) voltage regulator

Reason: A Zener diode works in its reverse breakdown region, where the voltage across it stays almost constant while the current changes widely. Connected in parallel with the load, it keeps the output voltage nearly constant, so it acts as a voltage regulator.


Question 6. All logic gates can be made by the repetitive use of:

  • a) OR gates
  • b) AND gates
  • c) NOT gates
  • d) NAND gates

Correct Answer: d) NAND gates

Reason: NAND (and NOR) gates are called universal gates: any basic gate (AND, OR, NOT) or any Boolean expression can be built using only NAND gates.


Question 7. What is the minimum number of NAND gates required to implement a NOT gate?

  • a) 1
  • b) 2
  • c) 3
  • d) 0

Correct Answer: a) 1

Reason: Join the two inputs of a NAND gate together and apply \(A\) to both. The output is

\[ Y=\overline{A\cdot A}=\overline A \]

which is the NOT operation. Only one NAND gate is needed.


Question 8. Which of the following is given by this logic circuit? (Input A goes to both inputs of one NAND gate, input B goes to both inputs of a second NAND gate, and the outputs of these two gates are the inputs of a third NAND gate.)

Class 12 Physics Chapter 22 Semiconductor Devices

Figure for Question 8

  • a) OR gate
  • b) AND gate
  • c) NAND gate
  • d) NOT gate

Correct Answer: a) OR gate

Reason: The first gate gives \(\overline{A\cdot A}=\overline A\) and the second gives \(\overline B\). The third gate gives

\[ Y=\overline{\overline A\cdot\overline B}=A+B \]

using De Morgan’s law. \(A+B\) is the output of an OR gate.

Question 9. Which of the following is given by this logic circuit? (Inputs A and B go into an OR gate, and the output of the OR gate goes into a NOT gate.)

Class 12 Physics Chapter 22 Semiconductor Devices

Figure for Question 9

  • a) OR gate
  • b) AND gate
  • c) NAND gate
  • d) NOR gate

Correct Answer: d) NOR gate

Reason: The OR gate gives \(A+B\) and the NOT gate inverts it, so \(Y=\overline{A+B}\). An OR gate followed by a NOT gate is a NOR (NOT-OR) gate.


Question 10. Boolean algebra is essentially based on:

  • a) logic
  • b) truth
  • c) number
  • d) symbol

Correct Answer: a) logic

Reason: Boolean algebra is the algebra of the truth values true and false (written 1 and 0). It is used to analyse and simplify logical statements and digital circuits, so it is essentially based on logic.

3. Numerical and Subjective Questions

Question 1. Potential barrier and characteristics of a p-n junction diode.

a) Explain the formation of the potential barrier and the depletion layer in a p-n junction.

When a p-type and an n-type semiconductor are joined, there is a concentration gradient: the p-region has a high concentration of holes (majority carriers) and the n-region has a high concentration of free electrons.

Because of this gradient, electrons diffuse from the n-side into the p-side and holes diffuse from the p-side into the n-side. An electron leaving the n-side leaves behind a fixed positive donor ion. An electron entering the p-side recombines with a hole and creates a fixed negative acceptor ion.

Near the junction there is therefore a region containing only immobile positive and negative ions, with no mobile charge carriers. This region is the depletion layer.

The positive ions on the n-side and the negative ions on the p-side set up an electric field directed from the n-side to the p-side. This field produces a potential difference across the junction, the barrier potential (or potential barrier) \(V_0\), which opposes the further diffusion of majority carriers. Equilibrium is reached when the drift current due to the field balances the diffusion current.

− + − + − + p-type (holes) n-type (electrons) Depletion layer Electric field E (n to p) · barrier potential V₀

Figure: Depletion layer and barrier potential of a p-n junction

b) Explain the forward and reverse characteristics of a p-n junction diode.

Forward bias. The positive terminal of the battery is connected to the p-type and the negative terminal to the n-type material. The applied voltage opposes the barrier potential, so the barrier becomes lower and the depletion layer narrower. Majority carriers can then cross the junction. Once the applied voltage exceeds the cut-in (knee) voltage (about 0.7 V for silicon), the current increases rapidly (exponentially) with the voltage. The diode has very low resistance in this state.

Reverse bias. The negative terminal is connected to the p-type and the positive terminal to the n-type material. The applied voltage adds to the barrier potential, so the depletion layer widens and the barrier increases. The flow of majority carriers almost stops. The strong field sweeps thermally generated minority carriers across the junction, giving a very small, nearly constant current called the reverse saturation current. If the reverse voltage is increased beyond the breakdown voltage, the reverse current suddenly increases greatly (avalanche or Zener breakdown), and an ordinary diode can be destroyed by the heat.

V I (mA) reverse bias forward bias 0.7 V (knee) small reverse current breakdown voltage V–I characteristic of a p-n junction diode

Figure: V–I characteristic of a p-n junction diode


Question 2. Junction diode, full-wave rectifier and Zener diode.

a) What is a junction diode? Explain a full-wave rectifier using two diodes.

A junction diode is a semiconductor device formed by joining a p-type and an n-type semiconductor. It conducts easily in forward bias and blocks the current in reverse bias.

Full-wave rectifier. It converts the whole of the input alternating cycle into pulsating direct current. It uses a centre-tapped transformer and two diodes \(D_1\) and \(D_2\). The ends of the secondary coil are connected to the p-sides of the two diodes, the n-sides are joined together and connected to the load resistor \(R_L\), and the other end of \(R_L\) is connected to the centre tap.

~AC input D₁ D₂ RL centre tap Full-wave rectifier using two diodes (centre-tap transformer)

Figure: Full-wave rectifier using two diodes

Working. In the positive half cycle the upper end of the secondary is positive with respect to the centre tap, so \(D_1\) is forward biased and conducts through \(R_L\), while \(D_2\) is reverse biased. In the negative half cycle the polarity reverses, \(D_2\) conducts and \(D_1\) is cut off. In both half cycles the current passes through \(R_L\) in the same direction, so the output across the load is unidirectional (pulsating direct current).

b) What will happen if one of the diodes is damaged?

If one diode (say \(D_2\)) becomes an open circuit, the rectifier works only in the half cycle in which the other diode is forward biased. It becomes a half-wave rectifier: the output exists for only half of each cycle, the ripple increases and the average output voltage and efficiency fall.

c) The output of a full-wave rectifier is pulsating direct current. Which device can be used to get a constant output voltage? Draw its symbol and its characteristics.

A Zener diode is used as a voltage regulator. It is connected in reverse bias, in parallel with the load, usually after a filter capacitor.

Zener diode symbol A (p) K (n) V I VZ breakdown: V constant at VZ Zener diode and its V–I characteristic

Figure: Symbol and characteristic of a Zener diode

In the forward region the characteristic is like that of an ordinary diode. In the reverse region, when the reverse voltage reaches the Zener breakdown voltage \(V_Z\), the current rises sharply, and the voltage across the diode stays almost constant at \(V_Z\) over a wide range of current. Therefore the output voltage across the load is held at \(V_Z\).

Question 3. Logic gates and the NAND gate.

a) What are logic gates? Give the truth table for a two-input NAND gate with its symbol.

Logic gates are the basic building blocks of digital electronic circuits. They perform logical operations based on Boolean algebra: they take one or more binary inputs (0 or 1) and give one binary output according to a logical rule.

A B Y = (A·B)′ NAND gate symbol

Figure: Symbol of a NAND gate

The NAND gate is “NOT AND”. Its output is 0 only when both inputs are 1; otherwise the output is 1: \(Y=\overline{A\cdot B}\).

ABY = (A·B)′
001
011
101
110

b) Explain why a NAND gate is considered a universal gate.

A NAND gate is a universal gate because the basic gates NOT, AND and OR can all be built using only NAND gates, so any digital circuit can be made from NAND gates alone.

NOT: join the two inputs together: \(Y=\overline{A\cdot A}=\overline A\).
AND: follow a NAND gate by a NAND-made NOT gate: \(Y=\overline{\overline{A\cdot B}}=A\cdot B\).
OR: invert each input with a NAND-made NOT gate and feed them into a NAND gate: \(Y=\overline{\overline A\cdot\overline B}=A+B\).

Making circuits from many identical gates is also cheaper and easier in integrated-circuit manufacture.


Question 4. Gates made from NOR and NAND gates.

a) Draw a circuit diagram to realise an AND gate from a NOR gate, with its truth table.

Use the De Morgan law: \(A\cdot B=\overline{\overline A+\overline B}\). So the inputs must be inverted and then fed into a NOR gate. A NOR gate becomes a NOT gate when its two inputs are tied together.

Input A goes to both inputs of NOR gate 1: \(\overline{A+A}=\overline A\).
Input B goes to both inputs of NOR gate 2: \(\overline{B+B}=\overline B\).
These outputs go into NOR gate 3: \(Y=\overline{\overline A+\overline B}=A\cdot B\).
A B Y = A·B NOR 1 NOR 2 NOR 3 AND gate built from three NOR gates

Figure: AND gate from three NOR gates

ABA′ (NOR 1)B′ (NOR 2)Y = (A′ + B′)′ (NOR 3)
00110
01100
10010
11001

b) Which gate will you get if you connect a NOT gate at the output of the circuit of part (a)?

The circuit of part (a) is an AND gate. A NOT gate at its output inverts the result, and an inverted AND gate is a NAND gate.

c) Show that the circuit given below acts as an OR gate using a truth table.

Class 12 Physics Chapter 22 Semiconductor Devices

Figure for Question 4

Input A passes through a NOT gate to give \(\overline A\), and input B passes through a NOT gate to give \(\overline B\). These two signals enter a NAND gate:

\[ Y=\overline{\overline A\cdot\overline B}=A+B \]
ABA′B′Y = (A′·B′)′A + B
001100
011011
100111
110011

The output column of the circuit is the same as the column of \(A+B\), so the circuit acts as an OR gate.

4. View PDF Notes

i. Handwritten Notes

ii. Typed PDF Notes

5. Frequently Asked Questions

What is a semiconductor? (definition in physics)
A semiconductor is a material whose electrical conductivity lies between that of a conductor and an insulator, and whose conductivity increases when the temperature rises or when impurities are added. Silicon and germanium are the most common examples. At absolute zero a pure semiconductor behaves as an insulator.
What topics are included in Chapter 22 Semiconductor Devices of NEB Class 12 Physics?
The chapter (6 hours, part of the unit Modern Physics) covers: 22.1 the p-n junction; 22.2 the semiconductor diode and its characteristics in forward and reverse bias; 22.3 full-wave rectification; 22.4 logic gates: NOT, OR, AND, NAND and NOR.
What are the types of semiconductors?
Semiconductors are of two types. An intrinsic semiconductor is pure (for example pure silicon or germanium). An extrinsic semiconductor is doped with an impurity: an n-type semiconductor is doped with a pentavalent impurity (such as phosphorus or arsenic) and has electrons as majority carriers, while a p-type semiconductor is doped with a trivalent impurity (such as boron or indium) and has holes as majority carriers.
What are examples of semiconductors?
Common examples are the elements silicon (Si) and germanium (Ge), and compounds such as gallium arsenide (GaAs). Devices made from semiconductors include diodes, transistors, light-emitting diodes, solar cells and integrated circuits.
What is a p-n junction and how is the depletion layer formed?
A p-n junction is formed when a p-type and an n-type semiconductor are joined. Electrons diffuse from the n-side to the p-side and holes diffuse from the p-side to the n-side. This leaves fixed positive ions on the n-side and fixed negative ions on the p-side near the junction. This region without mobile charge carriers is the depletion layer, and the potential difference across it (about 0.7 V for silicon and 0.3 V for germanium) is the barrier potential.
What is the semiconductor diagram of a p-n junction?
The diagram of a p-n junction shows a p-region (with holes) on the left, an n-region (with electrons) on the right, and a thin depletion layer in the middle containing negative ions on the p-side and positive ions on the n-side, with an electric field directed from the n-side to the p-side. The diagram is given on this page in Question 1.
What are forward bias and reverse bias?
In forward bias the p-side is connected to the positive terminal and the n-side to the negative terminal of the battery. The barrier is reduced and a large current flows once the applied voltage exceeds the cut-in voltage. In reverse bias the connections are reversed, the depletion layer widens and only a very small reverse saturation current (due to minority carriers) flows.
What is a rectifier and how does a full-wave rectifier work?
A rectifier converts alternating current into direct current. A full-wave rectifier uses two diodes and a centre-tapped transformer. In one half cycle diode D₁ conducts and in the other half cycle D₂ conducts, and in both cases the current passes through the load resistor in the same direction, so both halves of the input cycle are used and the output is pulsating direct current.
What happens if one diode of a full-wave rectifier is damaged?
If one diode becomes open, the circuit works only during the half cycle in which the other diode conducts. It behaves as a half-wave rectifier: the average output voltage falls and the ripple increases.
What is a Zener diode and what is it used for?
A Zener diode is a specially doped diode designed to work in the reverse breakdown region. In breakdown the voltage across it stays almost constant at the Zener voltage V_Z over a wide range of current, so it is used as a voltage regulator when connected in reverse bias in parallel with the load.
What are logic gates?
Logic gates are the basic building blocks of digital circuits. A logic gate has one or more inputs and one output, each taking the value 0 (low) or 1 (high), and the output follows a logical rule. The basic gates are NOT, OR and AND, and the combinations are NAND and NOR.
What are the Boolean expressions of the NOT, OR, AND, NAND and NOR gates?
NOT: Y = A′ (the complement of A). OR: Y = A + B. AND: Y = A·B. NAND: Y = (A·B)′. NOR: Y = (A + B)′.
Why are NAND and NOR called universal gates?
Any other gate (NOT, AND, OR) and therefore any digital circuit can be built using only NAND gates, or using only NOR gates. For example, joining the two inputs of a NAND gate gives a NOT gate.
What is a semiconductor chip and what are semiconductor companies and the semiconductor industry?
A semiconductor chip (integrated circuit) is a small piece of silicon on which millions or billions of diodes, transistors and logic gates are fabricated. The semiconductor industry consists of the companies that design and manufacture such chips for computers, mobile phones and other electronics. This is industry background and is not examined in the NEB syllabus; the syllabus deals with the physics of the p-n junction, diodes, rectifiers and logic gates.
Where can I get Class 12 Physics Chapter 22 Semiconductor Devices notes in PDF?
This page includes handwritten notes and typed PDF notes for Semiconductor Devices that you can view online, along with solved multiple choice questions and numericals.

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